Using the 14-ohm resistor example, the power dissipated equals I^2 R; if I = 0.05 A, P equals 0.035 W.

Using the 14-ohm resistor example, the power dissipated equals I^2 R; if I = 0.05 A, P equals 0.035 W.

• A. 0.035 W
• B. 0.7 W
• C. 0.5 W
• D. 0.0035 W

Answer: (A)

Power dissipated in a resistor is P = I^2 R. With a current of 0.05 A through a 14-ohm resistor, I^2 = (0.05)^2 = 0.0025. Multiplying by R gives 0.0025 × 14 = 0.035 W. You can also cross-check: the voltage across the resistor is V = IR = 0.05 × 14 = 0.7 V, so P = VI = 0.7 × 0.05 = 0.035 W. Another equivalent form, P = V^2 / R, yields (0.7^2)/14 = 0.49/14 = 0.035 W. So the power dissipated is 0.035 W; the other values don’t match these given numbers.

Power dissipated in a resistor is P = I^2 R. With a current of 0.05 A through a 14-ohm resistor, I^2 = (0.05)^2 = 0.0025. Multiplying by R gives 0.0025 × 14 = 0.035 W.

You can also cross-check: the voltage across the resistor is V = IR = 0.05 × 14 = 0.7 V, so P = VI = 0.7 × 0.05 = 0.035 W. Another equivalent form, P = V^2 / R, yields (0.7^2)/14 = 0.49/14 = 0.035 W.

So the power dissipated is 0.035 W; the other values don’t match these given numbers.